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[LeetCode]7-反转整数

来源:二三娱乐

前言


Python3 示例代码

class Solution:
    def reverse(self, x):
        minus = (x < 0)
        num = x
        if minus:
            num = x * (-1)
        num_unit = []
        while num > 0:
            unit = num % 10
            num_unit.append(unit)
            num = num // 10
            
        result = 0
        for i in range(0, len(num_unit)):
            result = result + num_unit[i] * 10 ** (len(num_unit) - 1 - i)
        if minus:
            result = result * (-1)
        
        if result > 2**31 -1 or result < -2 ** 31:
            return 0
        else:
            return result
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